4000+5*q+10*q^2=5*q+20*q^

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Solution for 4000+5*q+10*q^2=5*q+20*q^ equation: 



4000+5q+10q^2=5q+20q^

We move all terms to the left:

4000+5q+10q^2-(5q+20q^)=0

We get rid of parentheses

10q^2+5q-5q-20q^+4000=0

We add all the numbers together, and all the variables

10q^2-20q+4000=0

a = 10; b = -20; c = +4000;
Δ = b2-4ac
Δ = -202-4·10·4000
Δ = -159600
Delta is less than zero, so there is no solution for the equation

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